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Fun Math Problem
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Yochanan
Member
 
Join Date: May 2005
 
2005-12-19, 13:27

Well I thought it was fun, maybe I should just refer to it as a relatively fun math problem I made up. Here goes:

The 4:3 TV I have outside is a 27". I'm going to replace it with a 16:9 TV. What size 16:9 TV would I need to buy that would have the same height as my 4:3 TV?

Good Luck.

EDIT: Quick edit. Post questions for any clarifications you might need.
  quote
curiousuburb
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Join Date: May 2004
Location: that interweb thing
 
2005-12-19, 13:37

Are you including the bezel in that calculation, or purely the picture tube measured on the diagonal?

Is the bezel uniform size all the way around the tube? (many are deeper on the bottom to accomodate controls)
  quote
Kickaha
Veteran Member
 
Join Date: May 2004
 
2005-12-19, 13:47

height of current tube = x

27^2 = x^2 + (3/4x)^2
27^2 = (25/16)x^2
x = sqrt(27^2 * (16/25))

now plug that in for the other ratio:

Z^2 = x^2 + (9/16x)^2
Z = sqrt((26^2 * 16/25) + (9/16(27^2 * (16/25)))^2)

simple
  quote
alcimedes
I shot the sherrif.
 
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2005-12-19, 14:18

42"
  quote
bassplayinMacFiend
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Join Date: Jun 2004
 
2005-12-19, 15:39

Quote:
Originally Posted by Dr. Kickaha
height of current tube = x

27^2 = x^2 + (3/4x)^2
27^2 = (25/16)x^2
x = sqrt(27^2 * (16/25))

now plug that in for the other ratio:

Z^2 = x^2 + (9/16x)^2
Z = sqrt((26^2 * 16/25) + (9/16(27^2 * (16/25)))^2)

simple
The answer to your first equation, 21.6 makes sense, but the answer to your second equation, 263.262974, doesn't seem to make sense.
  quote
bassplayinMacFiend
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Join Date: Jun 2004
 
2005-12-19, 15:39

Quote:
Originally Posted by alcimedes
42"
You must've read my mind (or HHGTTG) because I replaced my 27" 4:3 CRT with a 42" 16:9 DLP.
  quote
BenP
Senior Member
 
Join Date: Jun 2005
 
2005-12-19, 15:57

Huh...I got 33".

Edit: I assumed the height was 3/4 of the width...is it the other way around?

Never mind. Funny, alcimedes. Real funny.
  quote
Bryson
Rocket Surgeon
 
Join Date: Feb 2005
Location: The Canadark
 
2005-12-19, 16:28

From non-mathematical means, I can say that the 32" widescreen TV we bought at work looked the same height as the 27" 4:3 TV it replaced.

Which is pretty much what you wanted to know, right?
  quote
EmC
Senior Member
 
Join Date: Jun 2004
Location: Columbus, Georgia
 
2005-12-19, 16:37

Quote:
Originally Posted by bassplayinMacFiend
The answer to your first equation, 21.6 makes sense, but the answer to your second equation, 263.262974, doesn't seem to make sense.
21.6 is the the width of the 4:3 TV not the height.

The answer is a 33" display.

Math

Last edited by EmC : 2005-12-19 at 16:48.
  quote
Bryson
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Join Date: Feb 2005
Location: The Canadark
 
2005-12-19, 16:39

Except most manufacturers make TVs in 28", 32", 36" and 42" screens. (Well, and 50", and even 70".) So 32" is the closest TV you can buy.
  quote
EmC
Senior Member
 
Join Date: Jun 2004
Location: Columbus, Georgia
 
2005-12-19, 16:51

Quote:
Originally Posted by Bryson
Except most manufacturers make TVs in 28", 32", 36" and 42" screens. (Well, and 50", and even 70".) So 32" is the closest TV you can buy.
Right, 32" is probably the closest you are going to get. The answer to the math problem is still 33".
  quote
Yochanan
Member
 
Join Date: May 2005
 
2005-12-19, 17:25

Quote:
Originally Posted by curiousuburb
Are you including the bezel in that calculation, or purely the picture tube measured on the diagonal?

Is the bezel uniform size all the way around the tube? (many are deeper on the bottom to accomodate controls)
We're only working with screen sizes here. Advertisers generally just call a TV a 27" no matter the bezel or bottom lip.
  quote
Yochanan
Member
 
Join Date: May 2005
 
2005-12-19, 17:27

Quote:
Originally Posted by Dr. Kickaha
height of current tube = x

27^2 = x^2 + (3/4x)^2
27^2 = (25/16)x^2
x = sqrt(27^2 * (16/25))

now plug that in for the other ratio:

Z^2 = x^2 + (9/16x)^2
Z = sqrt((26^2 * 16/25) + (9/16(27^2 * (16/25)))^2)

simple
I'm not bringing that to the store

What were your measurements for the height and width of the 4:3 TV? The height and width of the 16:9 TV?

I'm not so good anymore at following math equations like that (been out of school a while). How did you get the number 25 involved in any part of the equation?
  quote
Yochanan
Member
 
Join Date: May 2005
 
2005-12-19, 17:29

Quote:
Originally Posted by alcimedes
42"
Don't panic, but that's not what I got for an answer. But I'm not very good at this stuff anyway.
  quote
Yochanan
Member
 
Join Date: May 2005
 
2005-12-19, 17:30

Quote:
Originally Posted by BenP
Huh...I got 33".

Edit: I assumed the height was 3/4 of the width...is it the other way around?

Never mind. Funny, alcimedes. Real funny.
The height is 3/4 of the width.
  quote
Bryson
Rocket Surgeon
 
Join Date: Feb 2005
Location: The Canadark
 
2005-12-19, 17:36

Quote:
Originally Posted by Yochanan
Don't panic, but that's not what I got for an answer. But I'm not very good at this stuff anyway.
I think that was a Hitchhikers Guide reference, not an actual answer.
  quote
Kickaha
Veteran Member
 
Join Date: May 2004
 
2005-12-19, 17:41

Quote:
Originally Posted by Yochanan
I'm not bringing that to the store

What were your measurements for the height and width of the 4:3 TV? The height and width of the 16:9 TV?
First set solved for height of 27", second set plugged it into solving for diag of 16:9 ratio. Supposedly. See below.

Quote:
I'm not so good anymore at following math equations like that (been out of school a while). How did you get the number 25 involved in any part of the equation?
Because I did it too fast and squared 5 instead of 3. Also, I think I solved for same width, not same height. What can I say, it was off the top of my head.
  quote
thuh Freak
Finally broke the seal
 
Join Date: May 2004
 
2005-12-19, 17:42

Quote:
Originally Posted by Bryson
I think that was a Hitchhikers Guide reference, not an actual answer.
Don't Panic
  quote
alcimedes
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2005-12-19, 20:11

Correct. On all counts.
  quote
RowdyScot
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2005-12-19, 23:04

This thread just made my day
  quote
Brad
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Join Date: May 2004
Location: Zone of Pain
 
2005-12-19, 23:28

I guess they're not teaching the Pythagorean theorem to kids these days any more, eh?
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scratt
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2005-12-19, 23:32

You could always measure your current tv height and then when in the shop find one with the same height using the same tape measure....
  quote
billybobsky
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Join Date: May 2004
Location: Inner Swabia. If you have to ask twice, don't.
 
2005-12-20, 00:17

Why would you need to use the same tape measure?

I thought we standardized these things for a reason...
  quote
scratt
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2005-12-20, 01:42

Quote:
Originally Posted by billybobsky
Why would you need to use the same tape measure?

I thought we standardized these things for a reason...
To prevent user error... Using familiar tools leads to less errors when using them. i.e. Reading inches instead of cms etc.

In case there was a problem at the factory and the particular tape you used had been made incorrectly. As long as you are using the same one it will give you the same length reading even if it is incorrect.

Pedantic I know.. But then that's the hell I live in!

'Remember, measure life by the moments that take your breath away, not by how many breaths you take'
Extreme Sports Cafe | ESC's blog | scratt's blog | @thescratt
  quote
bassplayinMacFiend
Banging the Bottom End
 
Join Date: Jun 2004
 
2005-12-20, 19:38

Quote:
Originally Posted by Brad
I guess they're not teaching the Pythagorean theorem to kids these days any more, eh?
You mean that whole distance = sqrt (x^2 + y^2), or c^2 (hypotenuse) = a^2 + b^2?
  quote
bassplayinMacFiend
Banging the Bottom End
 
Join Date: Jun 2004
 
2005-12-20, 19:38

Quote:
Originally Posted by Brad
I guess they're not teaching the Pythagorean theorem to kids these days any more, eh?
You mean that whole distance = sqrt (x^2 + y^2), or c^2 (hypotenuse) = a^2 + b^2?
  quote
Brad
Selfish Heathen
 
Join Date: May 2004
Location: Zone of Pain
 
2005-12-20, 20:00

Yup. Along with some basic substitution, that's all you need to solve the problem.
  quote
shell
Member
 
Join Date: Oct 2005
 
2005-12-20, 23:33

Actually, considering the bezel your best bet is just sticking with the tape measure idea. Either that or "eyeball" it.
  quote
bassplayinMacFiend
Banging the Bottom End
 
Join Date: Jun 2004
 
2005-12-22, 08:12

Quote:
Originally Posted by Brad
Yup. Along with some basic substitution, that's all you need to solve the problem.
Pythagorus was the shizzle yo.
  quote
Windswept
On Pacific time
 
Join Date: May 2004
Location: Moderator's Pub
 
2005-12-23, 16:37

Quote:
Originally Posted by Dr. Kickaha
height of current tube = x

27^2 = x^2 + (3/4x)^2
27^2 = (25/16)x^2
x = sqrt(27^2 * (16/25))

now plug that in for the other ratio:

Z^2 = x^2 + (9/16x)^2
Z = sqrt((26^2 * 16/25) + (9/16(27^2 * (16/25)))^2)

simple


Okay, here's the way a *liberal arts major* does things ( ) haha :

I press myself against the screen at home and see that the length is from shoulder to fingertips and the height is from elbow to fingertips.

Then when, one day, I happen to be at the store, without a tape measure and without written-down measurements handy, I *always* have my shoulder, elbow and fingertips conveniently available to get a general idea of the new equipment I need.

Of course when I was shopping for a side-by-side refrigerator when my house was new, I took the most minute and exact measurements, because the space available was tight.

Even with my extreme care in measuring, the builder ended up making the space smaller than originally specified, and to accommodate the refrigerator I had picked, a carpenter had to come out and shorten the countertop so the fridge would fit. *sigh*
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